TRIG* STAR 2013-2014 SAMPLE PROBLEMS Sponsored by the National Society of Professional Surveyors

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TRIG* STAR
111//
2013-2014
SAMPLE PROBLEMS
Sponsored by the National Society of Professional Surveyors
TRIG—STAR PROBLEM IA LOCAL CONTEST
I
I
REQUIREL.ANSWER FORMAT
I
DISTANCES: NEAREST HUNDREDTH
ANGLES: DEGREES-MINUTES-SECONDS
(TO THE NEAREST SECOND)
I PRINT NAME: -----------
B
A
KNOWN: AB = 86.27, BC = 158.16
FIND:
DISTANCE AC =
(5 Points)
/ ABC =
(5 Points)
TRIG—STAR PROBLEM lB LOCAL CONTEST
F
E
H
Z EFG = 109-49'-58",
Z FEG = 47'—J59'-18"
KNOWN: EF = 62.25,
FIND:
DISTANCE EH =
(6 Points)
DISTANCE FH =
(6 Points)
DISTANCE FG =
(6 Points)
DISTANCE GI-I =
(6 Points)
/ EGF
(6 Points)
Page Total: ______ Points
Copyright - NSPS
PAGE 1 OF 3
LOCAL CONTEST
TRIG-STAR PROBLEM 2
REQUIRED ANSWER FORMAT
DISTANCES: NEAREST HUNDREDTH
ANGLES: DEGREES-MINUTES-SECONDS
(TO THE NEAREST SECOND)
B
-
-
-
A
D
KNOWN:
BC = 363.56, CD = 191.18,
/ BAD = 76-47'-50'
FIND:
Distance AB =
(10 Points)
Distance AD =
(10 Points)
Distance AC
(10 Points)
Page Total:
Copyright - NSPS
Points
SHEET 2 OF 3
TRIG-STAR PROBLEM 3
LOCAL CONTEST
REQUIRED ANSWER FORMAT
DISTANCES: NEAREST HUNDREDTH
AREAS: NEAREST WHOLE UNIT
A
rel
C
PROBLEM:
THE NORTH SIDE OF PARCEL ABCD IS BOUNDED BY A LOCAL HIGHWAY. DUE TO A
NEW HIGHWAY ALIGNMENT, THE NORTH SIDE OF PARCEL ABCD IS TO BE ROUNDED OUT
WITH A CIRCULAR ARC AE. THE RADIUS OF THE ARC IS 500.00 AND IS TANGENT TO
LINE AB AT POINT A. FIND THE NEW BOUNDARY DIMENSIONS OF PARCEL ABCD, SUCH
AS THE ARC LENGTH OF AE AND THE LENGTH OF LINE CE.
KNOWN:
AB = 300.00, BC = 412.31, CD = 200.00, DA = 400.00,
LBCD = 104-02'-10", LCDA & L.DAR = 90-00'-00",
& RADIUS OF ARC AE = 500.00
FIND:
ARC LENGTH
AE -
-------- (6 Points)
LENGTH EC -
(6 Points)
LENGTH BE
(6 Points)
AREA
AREA
ABCD
AECD
Page Total
Copyright - NSPS
(6 Points)
- (6 Points)
Points
SHEET 3 OF 3
TRIG-STAR ANSWER KEY
LOCAL CONTEST
PROBLEM 1-A
DISTANCE AC =
132.56
ANGLE ABC = 56-56'-38"
]
I
PROBLEM 1 -B
DISTANCE EH =
41.93
DISTANCE FH =
46.01
DISTANCE FO =
120.17
DISTANCE OH =
111.01
Z ABC
=I
22 - -30'-44"1
PROBLEM 2
DISTANCE AB =
281.66
DISTANCE AD = [
418.28
DISTANCE AC =
459.90
LENGTH AE
=
295.71
LENGTH EC
=
324.77
LENGTH BE
=
87.54
AREA ABCD
=[
100,000
AREA AECO
=
91,496
J
PROBLEM 3
Copyright - NSPS
1
TRIG—STAR MISCELLANEOUS DATA
RIGHT TRIANGLE FORMULAS
B
PYTHAGOREAN THEOREM: 02 + b 2
=
AREA: job
TRIGONOMETRIC FUNCTIONS: sin A =
b
C
cos A
tan A =
OBLIQUE TRIANGLE FORMULAS
B
LAW OF SINES:
LAW OF COSINES:
AC
b
AREA:
a
- b
- c
sin A - sin B - sin C
a 2 = b 2 + c 2 - 2bcCos A
bh
CIRCLE FORMULAS
DIAMETER = d
CIRCUMFERENCE:
AREA:
RADIUS = r
2lEr or
ltd
,tr 2
ONE DEGREE (1) OF ARC = 60 MINUTES (60') OF ARC
ONE MINUTE (1') OF ARC = 60 SECONDS (60") OF ARC
THEREFORE ONE DEGREE OF ARC (1) = 3600 SECONDS
OF ARC.
Copyright - NSFS

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